Package conary :: Package build :: Module use

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Module use

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Provides the build configuration as special dictionaries that directly export their namespaces.

Classes

Flag

Collection

CollectionWithFlag
CollectionWithFlag.

NoSuchUseFlagError

NoSuchArchFlagError

NoSuchSubArchFlagError

ArchCollection

MajorArch

SubArch

UseFlag

UseCollection

LocalFlag

LocalFlagCollection

PackageFlagCollection

PackageFlagPackageCollection

PackageFlag

Functions

allowUnknownFlags(value=True)

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setUsed(flagList)

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resetUsed()

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clearFlags()
Remove all build flags so that the set of flags can be repopulated

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clearLocalFlags()

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track(value=True)

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iterAll()

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getUsed()

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iterUsed()

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usedFlagsToFlavor(recipeName)

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allFlagsToFlavor(recipeName)

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localFlagsToFlavor(recipeName)

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platformFlagsToFlavor(recipeName=None)

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createFlavor(recipeName, *flagIterables, **kw)
create a dependency set consisting of all of the flags in the given flagIterables.

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setBuildFlagsFromFlavor(recipeName, flavor, error=True, warn=False)
Sets the truth of the build Flags based on the build flavor.

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Variables

Arch = Arch: {}

Use = Use: {}

LocalFlags = Flags: {}

PackageFlags = PackageFlags: {}

Function Details

createFlavor(recipeName, *flagIterables, **kw)

create a dependency set consisting of all of the flags in the given flagIterables. Note that is a broad category that includes lists, iterators, etc. RecipeName is the recipe which local flags should be relative to, can be set to None if there are definitely no local flags in the flagIterables.

setBuildFlagsFromFlavor(recipeName, flavor, error=True, warn=False)

Sets the truth of the build Flags based on the build flavor. All the set build flags must already exist. Flags not mentioned in this flavor will be untouched. XXX should this create flags as well as set them? Problem with that is that we don't know whether the flag is required or not based on the flavor; we would only be able to do as half-baked job